Please replace the precision with terms so that the code will stop at the user input's number of term(iteration):

The inputs are 1, 5 ,4

#include  #include  #include #include using namespace std::chrono; using namespace std; static double function(double x); int main() { double a; // Lower Guess or beginning of interval double b; // Upper Guess or end of interval double c; // variable for midpoint double precision; cout << "function(x) = x^3 +3x -5 "<> a; cout << " Enter end of interval: "; cin >> b; cout << " Enter precision of method: "; cin >> precision; // Check for opposite sign (Intermediate Value Theorem) if (function(a) * function(b) > 0.0f) { cout<< " Function has same signs at ends of interval"; return -1; } int iter=0; cout<=precision);//Terminating case auto stop = high_resolution_clock::now(); auto duration = duration_cast(stop - start); cout<<" Root = "<