Please round to the nearest thousandth $($i$.$e$.,0\mathrm{.}001).$

A soil has total weight $(W)=40lb$ and total volume $(V)=0\mathrm{.}45f{t}^3.$ The water content and the specific gravity of the soil solids are determined in the laboratory to be $18\%$ and $2\mathrm{.}05,$ respectively. Using this information, you can break down the total weight $($W$)$ into two variables: $1)$ Weight of solid $($Ws$)=33\mathrm{.}898lb$ and $2)$ Weight of water $($WW$)=6\mathrm{.}102lb.$ Calculate the followings:

Volume of solid $($Vs$)=f{t}^3$

Volume of water $(Vw)=f{t}^3$

Void ratio $(e)=$

Degree of saturation $(s)=\%$