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Problem 3: A sample of 10 students were surveyed and their pulse rates before and after exercise were recorded. The results are summarized in Question 19. Test for the hypothesis that the pulse rate of students after exercise is higher by 25, at a = 0.01. Let M1 and /2 be the pulse rates of students after and before exercise, respectively. If applicable, MD = M1 - M2 Null hypothesis: Ho: O MD = 25 O MD # 25 O MD 25 O MI - M2 = 25 O M1 - M2 # 25 O MI - M2 25Let M1 and /2 be the pulse rates of students after and before exercise, respectively. If applicable, MD = M1 - M2 Alternative hypothesis: Ha: O MD > 25 O MD 25Decision Rule: Reject Ho if . Otherwise, fail to reject Ho . Otc ta,u O Itcl > tal2,u O Itcl > tal2, (n-1) Otc ta, (n-1) O Zc Za/2 O Zc > ZaWhat is the critical value? If the critical value follows the 2- distribution, round off to the nearest hundredths. If the critical value follows the t- distribution, round off to the nearest thousandths. Do not use rounded values in your calculation. Try to use as much information (include as many digits after the decimal point) as you can from previously computed values. Input the nal answer only. Express the answer in decimal form and round off to the nearest thousandths. The following are the recorded pulse rates of the students: After 102 119 116 118 119 106 105 119 97 92 Before 75 70 77 73 75 72 64 70 77 65 Compute for Ze or to, whichever is appropriate.Decision: O Reject Ho O Fail to reject HoConclusion: O At the 1% level of significance, there is sufficient evidence to say that the pulse rate of students after exercise is higher by 25. At the 1% level of significance, there is insufficient evidence to say that the pulse rate of students after exercise is higher by 25