Please show every step how to get the yellow highlighted answers with the given information

$x-\frac{2}{4\mathrm{.}7}{F}_{ad}+\frac{2}{4\mathrm{.}7}{F}_{bd}=0F_{ad}=F_{bd}$

$y-\frac{1\mathrm{.}5}{4\mathrm{.}7}{F}_{ad}-\frac{1\mathrm{.}5}{4\mathrm{.}7}{F}_{bd}+\frac{4}{5\mathrm{.}7}{F}_{cd}=0F_{cd}=0\mathrm{.}91F_{ad}=0\mathrm{.}91F_{bd}$

$z\frac{4}{4\mathrm{.}7}{F}_{ad}+\frac{4}{4\mathrm{.}7}{F}_{bd}+\frac{4}{5\mathrm{.}7}{F}_{cd}-20=0$

$F_{ad}=F_{bd}=8\mathrm{.}5lb,$&$F_{cd}=7\mathrm{.}8lb$