Please show step by step solutions and explain. Thank you!

1) Imagine that we change LC-3 memory to contain 16MB of byte-addressable memory. In other words, 2²⁴ addresses, each holding 8 bits. Instructions are now 32 bits long (so now each instruction takes four consecutive memory locations).

a) How many bits are now needed for the PC?

b) How many bits are now needed for the IR?

c) How many bits are now needed for the MAR?

d) How many bits are now needed for the MDR?

e) Is instruction fetch faster, slower, or unaffected? Explain your answer

9 The tolliowing LC 3 instructions execute starting from the point shown by the comment ; start LC-3 execution here 1 0101 ee1 081 1 e8a8 2 8101 011 611 1 09800 3 0081 801 981 1 e1108 4 0801 e11 011 1 e01e1 7 0101 810 018 8 e0 811 8 8181 160 180 0 6 001 11 0181 010 10 00 100 13end LC-3 execution here After the code reaches the end of the code (the last comment). what bits are held in R1? And in R2? And in R3? And in R4? Lines 1-4 initialize the input registers, while lines 5-12 generate the output of the function, and store the result in register R2. What Boolean function is this code trying to implement? Specifically, identity the two input registers and the Bcolean function implemented R2-R? (mystery Boolean function?) R