Please show work and how to setup in QM for Windows to calculate answers when answering the questions below:

The seasonal yield of olives in Greece, is greatly influenced by the process of branch pruning. If olive trees is pruned every two weeks, output is increased. The pruning process, however, requires considerably more labor than permitting the olives to grow on their own and results in a smaller olive size. It also, though, permits olive trees to be spaced closer together. The yield of 1 barrel of olives by pruning requires 5 hours of labor and 1 acre of land. The production of olives by the normal process requires only 2 hours of labor but takes 2 acres of land. An olive grower has 250 hours of labor available and a total of 150 acres for growing. Because of the olive size difference, a barrel of olives produced on prune trees shows a profit of $20, whereas a barrel of regular olives shows a profit of $41. The grower has determined that because of uncertain demand, no more than 40 barrels of pruned olives should be produced (hint: 1 pruned < = 40).

1. What is the equation?

1. 5H + 2A <= 250
2. Z= 20H + 41A
3. 1P + 2R <= 150
4. Z= 20P + 41R
5. 5P + 2R <=250

2. What are the decision variables?

1. Pruned olives
2. Regular Olives
3. Pruned Olives and Regular Olives
4. Labor
5. Labor and Land
6. Land

3. The model has how many constraints (excluding those for non-negativity):

1. 1
2. 4
3. 3
4. 2

4. The amount of land acres slack generated by the models pruned olives only solution is:

1. 100
2. 110
3. 90
4. 50
5. 0

5. The total profit for the above models regular olives only solution is:

1. 2,140
2. 1,640
3. 800
4. 3,075
5. 2,275

6. The quantity for the above models pruned olives only alternative is:

1. 125
2. 0
3. 75
4. 150
5. 50
6. 40

7. The quantity for the above models regular olives only alternative is:

1. 125
2. 0
3. 75
4. 150
5. 50
6. 40

8. The number of barrels of pruned olives for the above models optimal solution is:

1. 62.5
2. 0
3. 40
4. 25
5. 75

9. The total profit for the above models optimal solution is:

1. 2,375
2. 1,640
3. 3,075
4. 2,275
5. 2,140