Question: please solve and show all steps (1 point) The graph of the equation x2 + xy + y2 = 7 is an ellipse lying obliquely

 please solve and show all steps (1 point) The graph ofthe equation x2 + xy + y2 = 7 is an ellipselying obliquely in the plane, as illustrated in the figure below. .1}

please solve and show all steps

a. Compute 2. dx dy _ dx _ b. The ellipse hastwo horizontal tangents. Find an equation of the lower one. The lowerhorizontal tangent line is defined by the equation y = c. The

(1 point) The graph of the equation x2 + xy + y2 = 7 is an ellipse lying obliquely in the plane, as illustrated in the figure below. .1} a. Compute 2. dx dy _ dx _ b. The ellipse has two horizontal tangents. Find an equation of the lower one. The lower horizontal tangent line is defined by the equation y = c. The ellipse has two vertical tangents. Find an equation of the rightmost one. The rightmost vertical tangent line is defined by the equation x = d. Find the point at which the rightmost vertical tangent line touches the ellipse. The rightmost vertical tangent line touches the ellipse at the p_c_>_i_r_1_t_ Hint: The horizontal tangent is of course characterized by % = 0. To find the vertical tangent use symmetry, or solve 3: = 0. f(x) = (Inx)s f' (x ) = (5In^4(x))/x f'(e4) =

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