Please solve it as C++

this is the starter code I got

#include

#include

using namespace std;

//xor operator ^: Hash code applied twice regenerates the original value:

m is message character and h is hash

// x=m^h and y=x^h then y (decoded message) is the same as m

void coder(char *x, char key,int length);

char *getMessage(char *request);

int main()

{

char *m = getMessage("Enter message to encode: ");

int length = strlen(m);

cout << length << endl;

//char *k = getMessage("Enter key ");//read in a key of arbitrary

length

coder(m, 'A', length);//A is the key. Encode message with key string

cout << m << endl;

coder(m, 'A', length);//Decode message. Decode message with key string

cout << m << endl;

delete(m); //no leaks

// delete(k);

return 0;

}

void coder(char *message, char key, int length)//make key an array

{

for (int i = 0; i < length; i++)

message[i] = message[i]^key;//cycle through the key

}

char *getMessage(char *request)

{

char temp[100], *p;

cout << request << " ";

cin >> temp;

p = new char(strlen(temp)+1);//+1 for terminating null

strcpy(p, temp);

return p;

}

you are to write a program that will encode and decode an input string using a key string. As each letter of the input string is encoded or decoded, the next character in the key string is to be used. When the end of the key string is found, the program needs to start back at the beginning of the key string as needed.