please solve question "e"

please solve question "e" to four decimal places.

Sample Number with etos 3 3 5 9 Determine the fraction defective in each sample. (Round your answers to A decimal a. places Sample 1 Taction defective 0152 0152 2 3 0254 4 0457 b. If the true fraction defective for this process is unknown, what is your estimate of it (Enter your answer as a percentage rounded to i dedmal place. Omit the sign In your response.) Estimate 25 O c. What is your estimate of the mean and standard deviation of the compling distribution of fractions defective for samples of this size (Round your intermediate calculations and final answers to a decimal places Mean Standard deviation 02541 0112 d. What controllimits would give an alpino risk of .03 for this process? (Round your intermediate calculations to 4 decinal places. Round your valoe to 2 decimal places and other answers to 4 decimal places) z Lower limit Go 0497 Upper limit e. What alpha dik would control to 0033 and 0470 provide (Round your intermediate calculations to A decimal places Round your value to 2 decimal places and alpha nsk value to decimal places 2= 192 @spherick 104907 Uring control. 0038 on 0470 is the process in control Z Table A Areas under the normal curve, O to z .00 .01 .02 Z .03 .04 .05 .06 .07 ,09 .08 0080 0.0 0.1 02 0.3 0.4 0000 0398 .0783 .1179 .1554 .0040 0438 0832 .1217 .1591 0120 0517 0910 .0160 0557 0948 .1331 .1700 .0478 0871 .1255 1628 0199 0596 0987 .1368 .1736 0239 0636 1026 .0279 .0675 1064 .1443 1808 0319 0714 .1103 1480 1844 ,0359 .0753 .1141 .1517 .1879 1293 1406 .1664 .1772 0.5 0.6 0.7 0.B .1915 2257 2580 2881 3159 .1950 2291 2611 2910 3186 .1985 2324 2642 2939 3212 2019 2357 2673 2967 3238 2054 2389 2703 2995 3264 2088 2422 2734 3023 3289 2123 2454 2764 3051 3315 2157 2486 2794 3078 3340 2190 2517 2823 3106 3365 2224 2549 2852 3133 3389 09 1.0 1.1 12 13 3413 3643 3849 4032 4192 3438 3665 3869 4049 4207 3461 3686 3888 4066 4222 3485 3708 3907 4082 4236 3508 3729 3925 4099 4251 3531 3749 3944 4115 4265 3554 3770 3962 4131 4279 3577 3790 3980 4147 4292 3599 3810 3997 4162 4306 3621 3830 4015 4177 4319 1.4 4370 4484 1.5 1.6 1.7 1.8 1.9 4332 4452 4554 4641 .4713 4345 4463 4564 4649 4719 4357 4474 4573 4656 4726 4582 .4664 4732 4382 4495 4591 4571 4739 4394 4505 4599 4678 4744 4406 4515 4608 4586 4750 4418 .4525 4616 4693 4756 4429 4535 4625 4699 4761 4441 4545 4633 4706 4767 4778 4826 20 2.1 22 23 24 4772 4821 4861 4893 4918 4854 4783 4830 4868 4898 4922 4789 4834 4871 4901 4925 4793 4838 4875 4904 4927 4799 4842 4878 4906 4928 4803 4846 4881 4909 4931 4808 4850 4884 4911 4932 4812 4854 4887 4913 4934 4817 4857 4890 4916 4936 4896 4920 4948 4961 25 26 27 28 29 4838 4953 4965 4974 4981 4940 4955 4966 4975 4982 4941 4956 4967 4976 4982 4943 4957 4968 4977 4983 4945 4959 4969 4977 4984 4946 1960 4970 4978 1984 4949 4962 4972 4979 4971 4951 4963 4973 4990 4986 4952 4964 4974 4981 4956 4979 4985 1985 3.0 4987 4987 4987 4988 4988 4989 4989 4990 4990 c. What is your estimate of the mean and standard deviation of the sampling distribution of fractions defective for samples of this size? Round your intermediate calculations and final answers to 4 decimal places) Mean 0254 0112 Standard deviation d. What control limits would give an alphe risk of 03 for this process? (Round your Intermediate calculations to 4 decimal places. Round your "x" value to 2 decimal places and other answers to 4 decimal places) Z Lower limit 6011 Upper limit 0497 e. Whet alpha risk would control limits of 0038 and 0470 provide? (Round your Intermediate calculations to 4 decimal places. Round your "z" value to 2 decimal places and alpha risk" value to 4 decimal places) 1.9727 alpha nisk = 0490 Using control limits of 0038 and 0470, is the process in control? yes no g. Suppose that the long-term fraction defective of the process is known to be 2 percent. What are the values of the mean and standard deviation of the sampling distribution? (Round your intermediate calculations and final answers to 2 decimal places) Mean Standard deviation 01 h. Constructo control cher for the processes coming e frection defective of 2 percent using two-me controllimis, the process in control No