Please solve the following proglem with Python 3. Please comment liberally.

# Create a generator that loops over the input iterable, # yielding one element at a time, but skipping duplicates

# Note the output should be in the same order as the input iterable

""" Test in the REPL: >>> from HW3 import unique >>> numbers = [4, 5, 2, 6, 2, 3, 5, 8] >>> nums = unique(numbers) >>> next(nums)

# should return: 4 >>> next(nums) 5 >>> next(nums) 2 >>> next(nums) 6 >>> next(nums) 3 >>> next(nums) 8 >>> next(nums) Traceback (most recent call last): File "", line 1, in StopIteration >>> You can also test it quickly with: >>> list(unique(numbers)) # should return: [4, 5, 2, 6, 3, 8] """ def unique(iterable): """Yield iterable elements in order, skipping duplicate values."""