Question: Please solve them, thank you! (a) (5 points) Prove that the function f(a:) = 3:2 sin(:1:) is uniformly continuous on any open interval (a, b)
Please solve them, thank you!

(a) (5 points) Prove that the function f(a:) = 3:2 sin(:1:) is uniformly continuous on any open interval (a, b) with a, b E R and a, 0, there is an x0 6 R such that |f'(a:0)| S e. Hint: can you use the Mean Value Theorem
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