Please solve this homework problem and show work on paper, I have attached extra formulas and tables to help solve the problem, thank you in advance.

\fPhysical Properties of Water vs. Temperature (SI Units) Temperature T ( C) Density p (kg/m]) Dynamic Viscosity J (N-5/m?) Kinematic Viscosity v (m /s) Vapor Pressure pv (kPa abs.) 0 999.8 1.80(10-" ) 1.80(10-) 0.681 5 1000.0 1.52(10-" ) 1.52(10-5) 0.872 10 999.7 1.31(10-* ) 1.31(10-5) 1.23 15 999.2 1.15(10- ) 1.15(10-3 ) 1.71 20 998.3 1.00(10-8) 1.00(10-5) 2.34 25 997.1 0.897(10-5) 0.898(10-6) 3.17 30 995.7 0.801(10-*) 0.804(10-*) 4.25 35 994.0 0.723(10-# ) 0.727(10-) 5.63 Roughness, Material Class. plastic O (smooth Concrete 0.003-0.03 0.9-9 Wood stave 0.0010 0.5 Rubber, smoothed 0.000033 0.01 Copper or brass tubing 0.000005 0.0015 Cast iran 0.26 Galvanized iron 0.0005 0.15 Wrought iron 0.00015 0.046 Stainless steel 0.00000 0.002 0.00015 0.045 Loss coefficients for pipe fittings KL Gate valve-fully opened 0.19 Globe valve-fully opened 10 Angle valve-fully opened 5 Ball valve-fully opened 0.05 Swing check valve 2 90 elbow (short radius) 0.9 90 long sweep elbow 0.6 450 bend (short radius) 0.4 180 return bend (short radius) 2 Tee for V along pipe run 0.4 Tee for V along branch 1.8Physical Properties of Water vs. Temperature (SI Units) Temperature T Density p Dynamic Viscosity Kinematic Vapor Pressure Pv (C) (kg/m') H (N.s/m?) Viscosity v (m?/s) (kPa abs.) 0 999.8 1.80(10-3) 1.80(10-) 0.681 5 1000.0 1.52(10-3) 1.52(10-) 0.872 10 999.7 1.31(10-3) 1.31(10-) 1.23 15 999.2 1.15(10-3) 1.15(10-) 1.71 20 998.3 1.00(10-3) 1.00(10-) 2.34 25 997.1 0.897(10-3) 0.898(10-) 3.17 30 995.7 0.801(10-3) 0.804(10-) 4.25 35 994.0 0.723(10-3) 0.727(10-6) 5.63 40 992.3 0.659(10-3) 0.664(10-) 7.38 45 990.2 0.599(10-3) 0.604(10-) 9.59 50 988.0 0.554(10-3) 0.561(10-6) 12.4Physical Properties of Liquids at Standard Atmospheric Pressure 101.3 kPa, and 20*C (SI Units) Liquid Density p Dynamic Viscosity Kinematic Viscosity Surface Tension (kg/m]) H (N-s/m?) v (m /s) o (N/m) Ethyl alcohol 789 1.19(10-3) 1.51(10*) 0.0229 Gasoline 726 0.317(10-3) 0.437(10-") 0.0221 Carbon 1590 0.958(10-2) 0.603(10-") 0.0269 tetrachloride Kerosene 814 1.92(10-3) 2.36(10-) 0.0293 Glycerin 1260 1.50 1. 19(10-3) 0.0633 Mercury 13 550 1.58(10-3) 0.117(10-) 0.466 Crude oil 880 30.2(10-3) 0.0344(10-3) 0.1- 0.09 0.07- -0.04 0.06 0.03 0.05 10.02 -0.015 0.04 0.01 0.008 0.03 0.006 0.004 0.025 0.002 0.02 1 0.O01 0.0008 -0.0006 0.015 0.0004 0.0002 0.0001 0.01 Smooth Pipe 0.000 05 0.009- 0.000 001 0.000 005- 0.008- 2 3 4 5 67 (103) (104) 2 3 4 5 67 9 2 3 4 5 67 9 (105) 2 3 4 5 67 9 (106) 2 3 4 567 9 (107) (10#) Re = VDProblem 3 (10 points): Learning Outcome #5 Glycerin at 20C flows through a copper pipe with 20 mm diameter and is discharged at Point C from a fully opened gate valve. The volumetric flow is 0.0003 m?3/s. Determine the pressure at Point A. The elbows can be modeled as 90 short radius elbows. Is the flow Laminar or Turbulent