Question: Please solve this question. This is related to recursion and induction. You may use 'base case', 'step case'. Thank you so much! EExercise 124. This

Please solve this question. This is related to recursion and induction. You may use 'base case', 'step case'. Thank you so much!

Please solve this question. This is related to recursion and induction. You

may use 'base case', 'step case'. Thank you so much! EExercise 124.

EExercise 124. This exercise is concerned with defining a mathematical entity of binary trees that corresponds to the BTree class. We refer to such a tree as a binary tree with labels from a set S, and use B Treess for the set of all these trees. (a) Give a definition, similar to Definition 48, of a mathematical entity of binary trees which corresponds to the B Tree class. (b) Recursively define an operation that takes two binary trees and returns a binary tree where the second argument has been added below the right-most leaf of the tree. (c) Write code which implements the operation from the previous part. Definition 48: tree A full binary tree with labels from a set S is given by Base case tree. For every element s of S there is a tree, trees, consisting of just one node labelled with the element s. Step case tree. Given two trees t and t' labelled over S, and an element s of S, there is a tree trees(t, t'). EExercise 124. This exercise is concerned with defining a mathematical entity of binary trees that corresponds to the BTree class. We refer to such a tree as a binary tree with labels from a set S, and use B Treess for the set of all these trees. (a) Give a definition, similar to Definition 48, of a mathematical entity of binary trees which corresponds to the B Tree class. (b) Recursively define an operation that takes two binary trees and returns a binary tree where the second argument has been added below the right-most leaf of the tree. (c) Write code which implements the operation from the previous part. Definition 48: tree A full binary tree with labels from a set S is given by Base case tree. For every element s of S there is a tree, trees, consisting of just one node labelled with the element s. Step case tree. Given two trees t and t' labelled over S, and an element s of S, there is a tree trees(t, t')

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