Please solve this step by step and explaining please. the answer is $5\mathrm{.}43$ tons per day $14\mathrm{.}5$ Determine the tons of lime $(CaO)$ required per day $($tpd$)$ for excess lime

softening of water with the following quality $($from Example $14\mathrm{.}2)$ if the

plant flow rate is $6mgd$:$C{a}^{2+}=150m\frac{g}{L}$ as $CaC{O}_3$;$M{g}^{2+}=100m\frac{g}{L}$

as $CaC{O}_3$;$N{a}^{+}=46m\frac{g}{L}$;$K^{+}=39m\frac{g}{L}$;$HC{O}_3^{-}=225m\frac{g}{L}$ as $CaC{O}_3$;

$S{O}_4^{2-}=72m\frac{g}{L}$;$C{l}^{-}=71m\frac{g}{L}.$

a$.3\mathrm{.}5$ tpd

b$.4\mathrm{.}5tpd$

c$.5\mathrm{.}4$ tpd

d$.6\mathrm{.}3tpd$