Please solve this using Matlab Code

created an "activewindow" vector of 0s and 1s which correspond to the times at which the solar panel is producing power. Now, use it to calculate in the overall length of time (in hours) for which the panel produces. Of many possible ways of solving this, one method could use vector math and another could use a looping structure with a counter. Once again, please solve each way and you should get the same result both methods but the result itself may be slightly different for the solarday1 data compared to the solarday2 data.

solarday1-10 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0,04 0.00 0.092 0.12 0.124 0.14 0.152 0.16# 0.452 1.244 2.196 2.676 2.824 2.964 3.108 3.208 3.296 3,4 3.455 3.54 2.828 3.72 3.716 3.728 3.604 3.628 3.392 3.444 1.916 2.628 2.944 1.08ee 1.952 1.628 2.288 2.912 1.532 1.080 1.9 1.912 1.76 1.452 1.184 0.936 0.584 0.304 0.196 0.092 0.04 0 0 0 0 0 0 00 0 0 00 0 0000 0] solarday2 [0 0 0 0 0 0 0 00 0 0000000 0 000 0 0 00 0 000 0.008 0.064 0.132 0.236 0.304 0.336 0.372 0.436 0.52 0.628 0.8 0.8 0.76 0.768 0.792 0.784 0.84 0.852 0.86 0.956 0.952 0.952 0.888 0.736 0.772 0.82 0.772 0.82 0.776 0.668 0.6 0.632 0.552 0.472 0.404 0.368 0.388 0.376 0.396 0.288 0.196 0.116 0.052 0.044 0.048 0.028 0 0 0 00 0 0 0 00 0 0 0 00 0 00 0 0 01 501armonth 1- [24.84 26.312 25.906 23.933 5.806 26.112 14.859 14.395 25.596 25.095 24.192 19.564 15.604 23.682 20.763 12.482 15.157 22.369 9.581 20.855 23.066 17.441 14.682 22.507 24.048 23.271 22.34 25.463 21.017 16.2621: time interval 0.25; units of hrs, 0.25 hours 15 minutes