$!!!$PLEASE SOLVE USING C LANGUAGE!! Part $2(35$ points$)$

Implement the following function in skeleton code $1$ab$1$part$2.$ c:

Your task in this part to fill in the missing function definitions in skeleton code lab$1$part$2.$ c$.$

main function will stay as it is$.$

Sample Run:

Enter the number of elements:

$5$

Enter $5$ elements:

$12345$

Array elements: $12345$

Enter the number of elements:

$5$

Enter $5$ elements:

$12345$

Array elements: $12345$

Equal

Average of the first array: $3$

Average of the second array: $3!!!!$HERE IS THE CODE STRUCTURE$/$SKELETON CODE lab$1$part$2.$c$.$ : #include

#define SIZE $500$

$//$ reads numbers from the standard input into arr,

$//$ and stores the number of read elements in the memory cell pointed to by nPtr

void readInput$($int arr$[],$ int $*$nPtr$)$;

$//$ prints the elements in arr$[0..($n$-1)]$

void printNumbers$($const int arr$[],$ int n$)$;

$//$ Let n be the minimum of n$1$ and n$2$ where n$1$ and n$2$ are the number of elements in

$//$ arr$1$ and arr$2,$ respectively.

$//$ Compare corresponding elements of arr$1$ and arr$2$ at each of the first n positions.

$//$

$//$ If arr$1$ and arr$2$ has the same value in each position:

$//$ Return $0$ if n$1==$ n$2$

$//$ Return $1$ if n$1>$ n$2$

$//$ Return $-1$ if n$1$ n$2$

$//$

$//$ If arr$1$ has a larger value than arr$2$ considering the first position from the

$//$ beginning at which arr$1$ and arr$2$ have a different value:

$//$ Return $1$

$//$

$//$ If arr$1$ has a smaller value than arr$2$ considering the first position from the

$//$ beginning at which arr$1$ and arr$2$ have a different value:

$//$ Return $-1$

int compareTwoArrays$($const int arr$1[],$ const int arr$2[],$ int n$1,$ int n$2)$;

int calculateAverage$($const int arr$[],$ int n$)$;

int main$()$

$\{$

int arr$1[$SIZE$]$;

int n$1$;

int arr$2[$SIZE$]$;

int n$2$;

readInput$($arr$1,$ &n$1)$;

printNumbers$($arr$1,$ n$1)$;

readInput$($arr$2,$ &n$2)$;

printNumbers$($arr$2,$ n$2)$;

int result $=$ compareTwoArrays$($arr$1,$ arr$2,$ n$1,$ n$2)$;

if $($result $==0)$

printf$("$

Equal

$")$;

else if $($result $==-1)$

printf$("$

Less than

$")$;

else if $($result $==1)$

printf$("$

Greater than

$")$;

int avg$1=$ calculateAverage$($arr$1,$ n$1)$;

int avg$2=$ calculateAverage$($arr$2,$ n$2)$;

printf$("$

Average of the first array: $\%$d

$",$ avg$1)$;

printf$("$Average of the second array: $\%$d

$",$ avg$2)$;

return $0$;

$\}$

void readInput$($int arr$[],$ int $*$nPtr$)$

$\{$

$//$ fill here

$\}$

void printNumbers$($const int arr$[],$ int n$)$

$\{$

$//$ fill here

$\}$

int compareTwoArrays$($const int arr$1[],$ const int arr$2[],$ int n$1,$ int n$2)$

$\{$

$//$ fill here

$\}$

int calculateAverage$($const int arr$[],$ int n$)$

$\{$

$//$ fill here

$\}$