Please Solve using PROLOG

Define a predicate classify/3 that takes a list of integers as an parameter and generates two lists, the first containing containing the even numbers from the original list and the second sublist containing the odd numbers from the original list. Your predicate should have the signature classify(List, Even, Odd).

Examples:

classify([8,7,6,5,4,3], Even, Odd). Even = [8,6,4] Odd = [7,5,3] 

?- classify([7,2,3,5,8], Even, Odd). Even = [2,8] Odd = [7,3,5] 

?- classify([-4,11,-7,9,0], Even, Odd). Even = [-4,0] Odd = [11,-7,9] 

?- classify([5,13,29], Even, Odd). Even = [] Odd = [5,13,29] 

?- classify([], Even, Odd). Even = [] Odd = []