1- Convert the following numbers to decimal. 3167 1B912 8059 2- Convert this decimal number 500...

 

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1- Convert the following numbers to decimal. 3167 1B912 8059 2- Convert this decimal number 500 to hexadecimal than to binary. 3- Convert to decimals: 10010.01012 201.758 4- Divide in binary and show the way you use it? 10010110/110. Show question and the reminder. 5- Multiply in binary and show all steps? Binary numbers 1011 by 1011. Also, the hexadecimal numbers 3A16 by 4B16. 6- Obtain the 1's complement of binary number 00111111. 7- Obtain the 2's complement of binary number 01110010. 8- What is the biggest positive number and biggest negative number that can be represented for a 10-bit number for the following numbering systems: 1's complement, 2's complement, signed magnitude. 9- Subtract using the 2's complement (first, convert subtrahend to 2's complement, then add it to the minuend)? If the result is negative, tell it is negative. 10011 - 01001 10- Convert 111110012 to BCD? 1- Convert the following numbers to decimal. 3167 1B912 8059 2- Convert this decimal number 500 to hexadecimal than to binary. 3- Convert to decimals: 10010.01012 201.758 4- Divide in binary and show the way you use it? 10010110/110. Show question and the reminder. 5- Multiply in binary and show all steps? Binary numbers 1011 by 1011. Also, the hexadecimal numbers 3A16 by 4B16. 6- Obtain the 1's complement of binary number 00111111. 7- Obtain the 2's complement of binary number 01110010. 8- What is the biggest positive number and biggest negative number that can be represented for a 10-bit number for the following numbering systems: 1's complement, 2's complement, signed magnitude. 9- Subtract using the 2's complement (first, convert subtrahend to 2's complement, then add it to the minuend)? If the result is negative, tell it is negative. 10011 - 01001 10- Convert 111110012 to BCD?

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316 7 to decimal 37 2 17 1 67 0 349 17 61 147 7 6 160 316 7 160 10 1B9 12 to decimal B11 112 2 1112 1 912 0 1144 1112 91 144 132 9 285 1B9 12 285 10 8... View the full answer