Please Solve With Steps

Digital Logic

8. The most simplified version of the function F implemented in the following circuit is: y F 1 a. F(x, y, z) = xy + z d. F(x, y, z) = 1 g. All of the above b. F(x, y, z) = x.y'+z+x'.y e. (b) and (c) h. None of the above c. F(x, y, z) = x. y'+z + x'.y.z' f. (a) and (b) 11. The Boolean expression as a POS of F implemented in the following circuit is (where D3 has the highest priority in the priority encoder): z A D 2x4 Decoder 0 w Ao D D2 D3 10 11 12 13 4x1 MUX F S 1 . . So B D. 4x2 D Priority Encoder D2 D: Z w a. F(x, y,z,w)=(x+y)(y+w) b. F(x,y,z, w) = (x + y)(x'+y+w)(x'+3+w) c. F(x,y,z, w)= x'.y'+y'.w'+x.z'.w' d. F(x, y, z, w)=(x + y)(y+w)(x'+z+w) e. F(x, y,z, w) = 0 f. F(x, y, z,w) = 1 g. All of the above h. None of the above