Question: Please translate this C++ code to MIPS assembly. I am having a hard time understanding how to call the getDigit function from inside the sumOfDoubleEvenPlace
Please translate this C++ code to MIPS assembly. I am having a hard time understanding how to call the getDigit function from inside the sumOfDoubleEvenPlace function so please make your work clear. Thank you
int sumOfDoub LeEvenPlace(int number) f int sum0 int digit; //Remove first odd digit number number / 10; while (number 0) { //Grab even placed digit digit- (number % 10); //Double the digit and pass it to getDigit, //Add result to sum sum + getDigit(diqit*2); sumsum+getDigit //Remove current even digit and the next odd digit. number -number/100 return Sum; int getDigit(int number) t int sum0 if (number
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