PLEASE USE BASIC PYTHON LANGUAGE SINCE THIS IS A BEGINNER CLASS PLEASE AND THANK YOU. No conditinals used please

Question $3($hw$2\_$q$3.$py$)$: Write a program that calculates the estimated time of arrival to a location given a number of random factors.

First, ask the user to enter the start time of the trip as a pair of integers $($hours and minutes$).$ Next, determine a random length in kilometers to the destination. The value should be between $46\mathrm{.}9$ and $287\mathrm{.}6.$ Calculate a random average speed for the trip in kilometers per hour in the range of $24\mathrm{.}141kph$ and $126\mathrm{.}3335kph.$ Both the trip length and average speed should be printed to $3$ decimal places.

Given the range and average speed, we can easily calculate the estimated time of arrival. In performing this calculation, be cautious that you represent the time correctly. That is$,$ if the time $60$ minutes, you will need to adjust the hour number and the minutes. $($A trip that starts at $56$ and takes $3$:$45$ is not simply $4$:$111!)$ Calculate, store, and print this value as the "base" arrival time.

However, this is New York and New Jersey; we don't go anywhere without traffic. Our trip will include $3$ accidents along the way that will impact our arrival time. Calculate $($randomly$)$ three time delays $($in the range of $5\mathrm{.}5$ to $43\mathrm{.}2$ minutes$)$ to account for the accident, and apply the additional delay times $($a the floor of the values$)$ to the arrival time. Your program will also print the three delays and the final arrival time at our destination. Finally, print the $($new$)$ average speed of the trip accounting for the added time delays.

Example Executions

Enter the start time in hours: $4$

Enter the start time in minutes: $56$

Length of trip: $48\mathrm{.}433$ kilometers.

Average speed during trip: $41\mathrm{.}857$ kilometers per hour.

Base arrival time: $6$:$5$

There were three delays as follows: $34,37,$ and $24$ minutes.

The final arrival time was: $7$:$40$

Final average speed of trip: $5\mathrm{.}236$ kilometers per hour.

Enter the start time in hours: $12$

Enter the start time in minutes: $35$

Length of trip: $219\mathrm{.}356$ kilometers.

Average speed during trip: $83\mathrm{.}171$ kilometers per hour.

Base arrival time: $15$:$13$

There were three delays as follows: $38,32,$ and $13$ minutes.

The final arrival time was: $16$:$36$

Final average speed of trip: $44\mathrm{.}205$ kilometers per hour.