Please use First Principle to answer my question.

Unit 2 Problem Set for 2.3 - 2.5 1. Differentiate. Write your answer simplest factored form. Then, determine f' (-1). A: 22 f (x) = (2x + 1)5(3x + 2)4 2. Determine the coordinate(s) of the point(s) on the curve f (x) = (2x - 1)3(x + 5) that have horizontal tangents. A: (,0). (- 3.- 395 307 512 3. Find the point(s) on the graph of y = _, where the slope of the tangent is -=. A: (6, 3) and (-2, 1) 4. Determine the derivative using the quotient rule. Do NOT simplify the derivative. s (x ) = - (-3x2 -1) (x+ 1) (x2 + 2x + 1)2 A: s'(x) = [-6x(x+1)+(-3x2-1)](x2+2x+1)"-(-3x2-1)(x+1)(2)(x2+2x+1)(2x+2) (x2+2x+1)4 5. Find ify = ut - 2u3 + it where u = 2vx - 1, when x = 5. A: 80 6. Determine a if m = -n3(9 -4n2), n = _ andr = v3x when x = 3. A: 35 12 7. Determine the derivative of the following. Do NOT simplify. m(x) = cx4 - v5x2 - cvx where c is a constant A : m' ( x ) = = (cx4 - 15x 2 - CVx ) 3 140x 3 - 1 ( 5x 2 - cV x ) 2( 10x - 5x 2 ) 1