Please verify my answers. Each specific question as each will have different requirements.

Data Preparation

SPSS data file from the data set by importing the M5 Excel file into SPSS.

Q1. Perform and Interpret a One-Way ANOVA.

A longitudinal project was conducted to study the executive and memory functions of elderly residents in a community. The participants were assessed every few years with a set of cognitive tests. Demographic and health information was also collected. The data set for Q1 and Q3 has been adapted from the data from that project.

The researchers would like to know if people's education level affects the amount of decline in executive function as they age. For this analysis,education level (Educ) is categorized into three levels and the change in executive function (EFChange) has been calculated by subtracting the EF score at the first testing session from the EF score at the second testing session.

Use theEFChange andEduc data to perform a one-way ANOVA with = .05 to answer the following question:

Is there a statistically significant difference in the change of executive function across different education levels?

A. What is the null hypothesis?

Null hypothesis (H0): there is no significant difference in the change of executive function across different education levels.

H0 : 1 = 2 = 3 ??

B. What are the dependent variable (DV) and the independent variable (IV)?

• Dependent Variable (DV) is the change in executive function (EFChange)
• Independent Variable (IV) is the Education level.

C. Perform the ANOVA in SPSS, including runningdescriptives and thehomogeneity of variance test.

POST HOC TESTS

D. Was the test for homogeneity of variance significant? Explain what the results mean relative to the data.

The test for homogeneity of variance is not significant because ( p =.456) p > 0.05 which means the assumption of equal variance is met.

[EF Change Based on Mean = .456 (Sig)]

Given that the Null hypothesis standsand there is no significance,we can assume that there is homogeneity of variances and the assumption for ANOVA is not violated.

E. Report the results of the one-way ANOVA using symbols in the APA format, including theF statistic, thep-value, and the effect size partial².

F(df between, df within) = F statistic, p = p-value, 2 = effect size.

Statistic: F(2, 47) = .290

Significance: p = .750

Effect size: 2 = 25.031/2055.150 = 0.012 [0.01217964625]

F. What is the decision about the null hypothesis (reject or fail to reject) based on the test result?

We reject the null hypothesis because the If the p-value is less than 0.05

The results of this ANOVA test suggest that there is not a statistically significant difference between the groups being compared, as indicated by the high p-value and the small effect size.

G. Create a bar graph or line graph to show the mean change in executive function for the different education groups

A. Your null hypothesis is correct. The null hypothesis for a one-way ANOVA is

Data Set

SubID	Gender	Educ	Age	EFChange	MemChange
1	1	2	65.8	-0.9	-1.88
2	1	1	66.9	2.07	-7.83
3	1	1	76.9	4.99	-13.71
4	1	1	79.9	-12.82	-8.99
5	1	1	67.5	-2.89	0.15
6	1	1	84.1	-8.44	-13.11
7	1	1	72.6	-0.68	-15.12
8	1	3	75.6	-5.78	0.51
10	1	2	78.0	-4.36	-0.05
13	1	3	67.2	2.13	0.05
14	1	2	70.0	2.5	1.48
18	1	1	70.6	-5	0.59
22	1	2	75.0	0.93	-5.65
24	1	3	69.5	1.19	0.97
29	1	1	65.2	0.87	-3.81
31	1	1	73.0	15.15	-12.88
38	1	2	66.0	2.64	-7.89
39	1	3	71.4	-1.67	5.55
40	1	3	75.8	-1.25	5.82
41	1	3	65.4	-5.16	-3.91
44	1	3	69.3	8.01	-0.89
45	1	2	68.1	1.32	-1.60
47	1	2	67.8	0.44	-9.81
49	1	2	71.9	1.31	-4.14
9	2	1	69.6	-11.92	0.07
11	2	1	66.3	13.25	-1.30
12	2	2	65.1	-4.56	-3.49
15	2	2	77.7	-6.79	-2.00
16	2	2	69.4	1.28	-0.99
17	2	2	65.3	-6.67	-3.67
19	2	3	78.4	-11.24	-0.25
20	2	2	69.6	-9.98	-1.10
21	2	1	65.8	-4.23	-0.98
23	2	3	68.5	-10.52	2.21
25	2	1	67.0	2.13	0.50
26	2	1	69.9	-1.01	-0.28
27	2	3	86.6	-9.38	-0.96
28	2	2	68.7	1	-1.66
30	2	1	76.8	-9.1	-5.72
32	2	3	66.7	-1.44	1.84
33	2	1	65.5	-1.5	2.06
34	2	2	72.8	-2.26	4.97
35	2	3	79.5	-0.53	2.72
36	2	1	72.9	4.56	-1.45
37	2	3	69.7	7.85	-2.10
42	2	3	67.0	-7.72	-3.61
43	2	3	79.2	9.5	-2.39
46	2	2	77.5	-16.96	1.15
48	2	3	75.8	-1.77	-1.44
50	2	2	68.3	-2.68	-0.48

Codebook

Variable Name	Description	Values
Gender	Gender	1 - Female
		2 - Male
Educ	Education	1 - High school or lower
		2 - Bachelor's degree
		3 - Graduate studies
Age	Age at 1st test session	Number of years
EFChange	Change in executive function from 1st test session to 2nd test session	Test Score
MemChange	Change in memory function from 1st test session to second test session	Test Score