Question: Consider the (real-variable) integral -k dx X 1:= = fo x2 + 2x cos 6+1 where k is real, the numerator in the integrand

Consider the (real-variable) integral -k dx X 1:= = fo x2 +

Consider the (real-variable) integral -k dx X 1:= = fo x2 + 2x cos 6+1 where k is real, the numerator in the integrand is real by definition, and 0 < < T. a. For what values of k does this integral converge? sin ko - sin kt sin b. Use a keyhole contour to show that I

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