Pls answer Asap Bending moment equation:

In this exercise, we consider a simply supported beam shown in the figure, subject to linearly varying load.

The following parameters are given:

$L_1=3m$

$L_2=1\mathrm{.}5m$

$w_0=300\frac{N}{m}$

Let's start with equations of global equilibrium to determine the reaction forces:

$x_2$

In the figure above $P_1$ is the resultant force due to distributed load on the beam section $AC.$ Calculate its value and the point $x_1,$ where it is applied:

$P_1=\frac{1}{2}{w}_0{L}_1=$

$x_1=\frac{2}{3}{L}_1=$

Calculate the resultant force $P_2$ and the point of its application for section $CB$ :

$P_2$ :

$x_2=$

Next, write equations of equilibrium for forces and moments to find reaction forces $R_A$ and $B$

$R_A{?}_{R^{**}}$

where is it aoolied?

where is it applied?

$P=P(x)$ is calculated as an area of the linearly distributed load and can be expressed as

$P=A{x}^2$

where

$A=$

and

$x_P=\frac{2}{3}x$

The equation of moment equilibrium with respect to point $x$ is given by$-$

$M+P\frac{x}{3}-R_{A}x=0$

from where $we$ can write $M=M(x)in$ the form

$M(x)=B{x}^3+Cx$

what are coefficients $B$ and $C?$

$B=$

$C=$

What is the value of $M(x)$ at $x=L_1?$ If your calculations are correct, you should arrive to:

$M(x=L_1)=450\mathrm{.}0N*m1$