PLZ READ

Requirements:

use $2$ functions

paremeter to first function should be the size of the array, than you fill up the array

in main, pass size to find median function

$.$Use passing and returning

$.$must use this lines of code

$.$add $a$1,$$$0,$$t$5$ # Passing to function by $a$1$

add $a$2,$$$0,$$t$6$ # Passing to function by $a$2$

$.$add $t$0,$ $v$1,$ $$0$

$.$add $t$5,$$$0,$$a$1$ # Passing to function by $a$1$

add $t$6,$$$0,$$a$2$ # Passing to function by $a$2$

$.$add $v$1,$ $t$7,$ $$0$ # returning the result to main

Look at photo provided plz uses Mips Main prints the madian

How many number you like to enter: $9$

Enter number $1$: $10$

Enter number $2$: $20$

Enter number $3$: $30$

Enter number $4$: $40$

Enter number $5$: $50$

Enter number $6$: $60$

Enter number $7$: $70$

Enter number $8$: $80$

Enter number $9$: $90$

The median is: $50$

How many number you like to enter: $6$

Enter number $1$: $11$

Enter number $2$: $15$

Enter number $3$: $16$

Enter number $4$: $18$

Enter number $5$: $212$

Enter number $6$: $220$

The median is: $17$

$===============================$

How many number you like to enter: $6$

Enter number $1$: $11$

Enter number $2$: $15$

Enter number $3$: $18$

Enter number $5$:$23$

Enter number $6$: $220$

Enter number $7$: $221$

The median is: $20$

$===============================$

the middle is $20\mathrm{.}5$ in the last case but since we only deal with integer we get the integer part

which is $20.$

PLZ READ

Requirements:

use $2$ functions

paremeter to first function should be the size of the array, than you fill up the array

in main, pass size to find median function

$.$Use passing and returning

$.$must use this lines of code

$.$add $a$1,$$$0,$$t$5$ # Passing to function by $a$1$

add $a$2,$$$0,$$t$6$ # Passing to function by $a$2$

$.$add $t$0,$ $v$1,$ $$0$

$.$add $t$5,$$$0,$$a$1$ # Passing to function by $a$1$

add $t$6,$$$0,$$a$2$ # Passing to function by $a$2$

$.$add $v$1,$ $t$7,$ $$0$ # returning the result to main