plz see photos for instructions. must be written in java. thank you

Create a Java program that will take inputs of A, B, and C (as integers) from users. Reject the inputs if both A and B are zeros, otherwise, find two points on the line and display them in the form of (x, y). A sample output looks: Enter AS OK OK 21 and Message Equation 3x+4y+5=0 Includes two points: (1.0,-1.25) (2.0,-2.0) ok The general form of the equation of a straight line can be expressed as Ax+By+C =0 with a condition that A and B cannot both be zero. This equation can also be expressed as: y . Given a straight line, 2x -y + 1 = 0, one can re-write the equation as y=2x+1 and then use it to find few points that are on the line. Here are some example values: I y = 2x +1 y = 2 X (-1) + 1 = -1 y = 2 x 0+ 1=1 y= 2 x 1 + 1 =3 y = 2 x 2 + 1 = 5 Point -1, -1) (0, 1) (1,3) (2,5) 2