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$I_a=\frac{120(8{)}^3}{12}+1208(17\mathrm{.}6{)}^2+\frac{8(80{)}^3}{12}+808(26\mathrm{.}4{)}^2$

$=1\mathrm{.}09{10}^{6}m{m}^4$

$I_{ny}=\frac{8(120{)}^3}{12}+1208(8{)}^2+\frac{80(8{)}^3}{12}+808(12{)}^2$

$=1\mathrm{.}31{10}^{6}m{m}^4$

$I_n=1208817\mathrm{.}6+808(-12)(-26\mathrm{.}4)$

$=0\mathrm{.}34{10}^{6}m{m}^4$

Find bending stress at the corner points using

$1.$principal axis method

$2.$ Neutral axis method

Generalised method of bending stress distribution