Point $A$ of the circular disk is at the angular position $=0$ at time $t=0.$ The disk has angular velocity ${}_0=0\mathrm{.}14ra\frac{d}{s}$ at $t=0$ and subsequently experiences an angular acceleration $a=3\mathrm{.}0$ t where $t$ is in seconds, and $a$ is in radians per second squared. Determine the velocity and acceleration of point $A$ in terms of fixed i and $j$ unit vectors at time $t=2\mathrm{.}2s.$

Assume $r=140mm.$

Answers:

$v_A=(i+j)\frac{m}{n}$

$a_A=(5i+i,j)\frac{m}{s^2}$