Pointer Arithmetic II Idiff (C1,C2) Find The Number Of Characters Between Two Letters Of The Alphabet Using Pointer Arithmetic. Include C2 In The Count But Not Cl. For Example Idiff('A','E') == 4 Is True And Diff('E','A') == -4 Is True. Check For Errors. If Either Letter Is Not A Capital Letter, Return A Negative Number Less Than -26.