Points$]$

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Suppose a $6\mathrm{.}9{10}^{10}kg$ meteoroid struck the earth at the equator with a speed $v=2{10}^4\frac{m}{s},$ as shown in Fig, $11-27$ and remained stuck $($near the surface$).$ What is the change in the length of the day $($in seconds$)?$ For moments of inertia of some common geometries, click here. If needed, the mass of the Earth is $5\mathrm{.}97{10}^{24}kg$ and the radius of the Earth is $6\mathrm{.}38{10}^{6}m.$ Note that Desmos may be do a better job than your calculators of calculating the difference of two numbers which are very

dose.to each other.

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