Population $=72,173$

Area $=70$ sq mi

Registered vehicles $=26,685$

Single$-$family housing units $=15,675$

Apartment units $=7,567$

Retail employment $=5,502$

Nonretail employment $=27,324$

Student attendance $=28,551$

Average household income $=$$$17,500$

Transportation analysigzones $=129$

The results of the cross$-$classification analysis are as follows.

Total trips produced for study area $=282,150$ per day

Home$-$to$-$work trips: $13\%(36,680)$

Home$-$to$-$nonwork trips: $62\%(174,933)$

Nonhome$-$based trips: $25\%(70,537)$

The attraction rates for the area have been developed using the following assumptions.

$100$ percent of home$-$to$-$work trips go to employment locations.

Home$-$to$-$nonwork trips are divided into the following types.

Visit friends: $10\%$

Shopping: $60\%$

School: $10\%$

Nonretail employment:$20\%$

Nonhome$-$based trips are divided into the following types.

Other employment area $($nonretail$)$: $60\%$

Shopping: $40\%$

Determine the number of home$-$to$-$work, home$-$to$-$nonwork, and nonhome$-$based trips attracted to a zone

with the following characteristics: population $=1440$; dwelling units $=630$; retail employment $=40$;

nonretail employment $=650$; school attendance $=0.($Assume that the number of home$-$to$-$work trips is

proportional to employment in the zone. Assume that the number of trips to visit friends is proportional

to the number of dwelling units in the zone. Assume that the number of shopping trips is proportional to

retail employment in the zone. Assume that the number of trips to school is proportional to school

attendance in the zone. Assume that the number of trips to nonretail employment is proportional to

nonretail employment in the zone.$)$Population $=72,173$

Area $=70$ sq mi

Registered vehicles $=26,685$

Single$-$family housing units $=15,675$

Apartment units $=7,567$

Retail employment $=5,502$

Nonretail employment $=27,324$

Student attendance $=28,551$

Average household income $=$$$17,500$

Transportation analysigzones $=129$

The results of the cross$-$classification analysis are as follows.

Total trips produced for study area $=282,150$ per day

Home$-$to$-$work trips: $13\%(36,680)$

Home$-$to$-$nonwork trips: $62\%(174,933)$

Nonhome$-$based trips: $25\%(70,537)$

The attraction rates for the area have been developed using the following assumptions.

$100$ percent of home$-$to$-$work trips go to employment locations.

Home$-$to$-$nonwork trips are divided into the following types.

Visit friends: $10\%$

Shopping: $60\%$

School: $10\%$

Nonretail employment:$20\%$

Nonhome$-$based trips are divided into the following types.

Other employment area $($nonretail$)$: $60\%$

Shopping: $40\%$

Determine the number of home$-$to$-$work, home$-$to$-$nonwork, and nonhome$-$based trips attracted to a zone

with the following characteristics: population $=1440$; dwelling units $=630$; retail employment $=40$;

nonretail employment $=650$; school attendance $=0.($Assume that the number of home$-$to$-$work trips is

proportional to employment in the zone. Assume that the number of trips to visit friends is proportional

to the number of dwelling units in the zone. Assume that the number of shopping trips is proportional to

retail employment in the zone. Assume that the number of trips to school is proportional to school

attendance in the zone. Assume that the number of trips to nonretail employment is proportional to

nonretail employment in the zone.$)$