Question: Position (m) Force (n) k(x - Xequ) mg(x - Xequ) (J) 0.22 0.1 0.255 0.2 0.29 0.3 0.33 0.4 0.365 0.5 0.395 0.6 0.435

Position (m) Force (n) k(x - Xequ) mg(x - Xequ) (J) 0.220.1 0.255 0.2 0.29 0.3 0.33 0.4 0.365 0.5 0.395 0.6 0.435

Position (m) Force (n) k(x - Xequ) mg(x - Xequ) (J) 0.22 0.1 0.255 0.2 0.29 0.3 0.33 0.4 0.365 0.5 0.395 0.6 0.435 0.7 0.465 0.8 0.5 0.9 0.54 1 0.605 1.2 0.68 1.4 0.715 1.5 Force (n) 1.6 1.4 1.2 0.8 0.6 0.4 0.2 0 Force vs Position y=2.8385x-0.5269 0 0.2 0.4 0.6 0.8 Position (m) What is the value of the spring constant k (magnitude and units)? What is the equilibrium position of the free end of the spring in units of cm, i.e. in your graph, what is x (in m) when y = 0? Is the gravitational potential energy lost equal to the elastic potential energy stored in the spring? If not, approximately how much of the work done by gravity is stored in the spring, and what do you think happened to the rest of it?

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