possidie

For the given function $f(x)$ and the given values of $c$ and $>0,$ find $L=\underset{xc}{lim}f(x).$

Then determine the largest value for $>0$ such that $|f(x)-L|<mi></mi>$ whenever

$f(x)=\frac{x^2-144}{x-12},c=12,=0\mathrm{.}08$

The value of $L$ is

$($Simplify your answer.$)$

The largest value of $>0$ such that $|f(x)-L|<mi></mi>$ whenever is $$

$($Simplify your answer. Round to the nearest hundredth as needed.$)$