Question: POSTLAB: 8. Volumetric Analysis answer correctly with solutions A 0.432 gram sample of pure NH4 Cl was treated with 35.0 mL of 1.00 M NaOH

POSTLAB: 8. Volumetric Analysis answer correctly with solutions

A 0.432 gram sample of pure NH4 Cl was treated with 35.0 mL of 1.00 M NaOH and heated to drive off the NH3. How many mols of NaOH are needed to react with the NH, Cl? mol How many milliliters of 0.640 M HCI are needed for the back titration? mL

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