Question: Powered by Chegg AI 1 st step All steps Answer only Step 1 scanf ( % d , &b ) ; printf (

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1st step
All steps
Answer only
Step 1
scanf("%d", &b); printf("Start "); if (b<=5) printf("Hello ");
Explanation:
This part of the code reads an integer input for variable 'b'. If the value of 'b' is less than or equal to 5, it prints 'Hello'.
Step 2
else if(b>5) printf("World ");
Explanation:
If the value of 'b' is greater than 5, it prints 'World'.
Step 3
else if ((b>=2)&&(b<10)) printf("UIU "); else if ((b>2)||(b<=10)) printf("CSE ");
Explanation:
These conditions are never reached because the previous conditions already cover all possible values of 'b'.
Step 4
else printf("Error "); printf("Stop");
Explanation:
This part of the code is also never reached because the previous conditions already cover all possible values of 'b'. The code always ends by printing 'Stop'.
Answer
For b=4, the output is 'Start Hello Stop'. For b=5, the output is 'Start Hello Stop'. For b=10, the output is 'Start World Stop'. For b=12, the output is 'Start World Stop'

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