Practice Problem: $1$ The working fluid, in a steady flow process flows at a rate of $220k\frac{g}{m}in.$

The fluid rejects $100k\frac{J}{s}$ passing through the system. The conditions of the fluid at inlet and

outlet are given as : $v_1=320\frac{m}{s},p_1=\frac{6\mathrm{.}0}{b}ar,u_1=2000k\frac{J}{k}g,v_1=0\mathrm{.}36\frac{m^3}{k}g$ and $v_2=$

$140\frac{m}{s},p_2=\frac{1\mathrm{.}2}{b}ar,u_2=1400k\frac{J}{k}g,v_2=1\mathrm{.}3\frac{m^3}{k}g.$ The suffix $1$ indicates the condition at inlet

and $2$ indicates at outlet of the system.

Calculate the power capacity of the system.

Note: The change in Potential energy may be neglected.