Practice similar

Attempt $4$: $2$ attempts remaining.

Solve $4x{y}^{\text{'}}-8y=x^{-3},y(1)=-7.$

$($a$)$ Identify the integrating factor, $(x).$

$(x)=$

$$

$($b$)$ Find the general solution.

$y(x{)}^{-}=$

$$

Note: Use C for the arbitrary constant.

$($c$)$ Solve the initial value problem $y(1)=-7.$

$y(x)=$

$$