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$x^{\text{'}}=-(x+3\mathrm{.}5)(x+2{)}^3(x+0\mathrm{.}5{)}^2(x-0\mathrm{.}5)\frac{-}{0\mathrm{.}13}\frac{-}{0\mathrm{.}13}\frac{-}{0\mathrm{.}13}$