Pratt Bridge $($Caso $3)$

${\displaystyle \underset{?}{\overset{?}{}}}Fx=0$

${\displaystyle \underset{?}{\overset{?}{}}}MA=0$

$-BHY(12)+67\mathrm{.}5(9)=0$

RHY $=\frac{-67\mathrm{.}5(9)}{-12}$

RHY $=50\mathrm{.}625$

$MH=0$

RAY$(12)-67\mathrm{.}5(3)=0$

BAY$=\frac{67\mathrm{.}5(3)}{12}$

RAY$=16\mathrm{.}875$

I already have the reaction of the pratt bridge know i need the forces of the trusses joints using the joints and section method combine.