Question: Precalculus You have the functions f(x) = 3x + 1 and g(x) = |x - 1| i) Let h(x) = f(x)g(x). Explain why the

Precalculus You have the functions f(x) = 3x + 1 and g(x)

Precalculus You have the functions f(x) = 3x + 1 and g(x) = |x - 1| i) Let h(x) = f(x)g(x). Explain why the Product Rule can be used to compute h`(0) but cannot be used to compute h`(1). Then, compute h`(0). (What are the theorem's hypotheses? Why do they apply?)

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