Question: Previous answer on Chegg was wrong, please check that before answering exercise 0.2 in exercise 0.0, we applied two different operators, addition and multiplication; now

Previous answer on Chegg was wrong, please check that before answering

exercise 0.2 in exercise 0.0, we applied two different operators, addition and multiplication; now consider applying the same operator many times in an expression; can you explain why 6/2/3 is 1 ? what is the other choice for this value, if we had used a different rule? exercise 0.3 can you find an arithmetic operator that uses a different rule than exercise 0.2 ? (tricky)

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