$($Previous answer was incorrect$)$

A hydraulic jump is formed in an open channel of a rectangular cross$-$section with width $($b$).$ The water depths upstream and downstream of the jump are $(y1)$ and $(y2)$ respectively.

Given the values of $y1[m],y2[m],$ and $b[m],$ calculate the discharge in the channel $(Q)$ in $[$Lit$/$s$]$

Givens:

$y1=0\mathrm{.}733m$

$y2=5\mathrm{.}459m$

$b=1\mathrm{.}426m$