a) In terms of the timing and gradient parameters shown in Fig. 9.6, show that the...

  

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a) In terms of the timing and gradient parameters shown in Fig. 9.6, show that the phase during the first (negative) gradient lobe is $(z, t) Gz(t - t1) - yAB(2)(t – 27) t1 <t< t2 (9.43) b) Show that the phase during the second (positive) gradient lobe is t3 <t < t4 (9.44) $(z, t) = yGz(t, – t1) – YAB(2)(t – 27) – Gz(t – t3) which is identical to (9.42). I (Robert_W_Brown;_Yu-Chung_N_Cheng: E_Mark_Haacke;(z-lib.org).pdf - Adobe Reader File Edit View Window Help Оpen (192 of 978) Tools Fill & Sign Comment 158 100% Sign In • Export PDF • Create PDF v Edit PDF Adobe Acrobat Pro 158 Chapter 9. One-Dimensional Fourier Imaging Easily edit text and images in PDF documents Start Now (T)y (T/2) • Send Files > Store Files rf t, G read t, ADC T. Fig. 9.6: Sequence diagram for a spin echo 1D imaging experiment with a 7-pulse preceding two gradient lobes of opposite polarity. The subscripts on the rf flip angles again denote the direction of the applied magnetic field B1. 图 a) In terms of the timing and gradient parameters shown in Fig. 9.6, show that the phase during the first (negative) gradient lobe is $(z, t) Gz(t - t1) - yAB(2)(t – 27) t1 <t< t2 (9.43) b) Show that the phase during the second (positive) gradient lobe is t3 <t < t4 (9.44) $(z, t) = yGz(t, – t1) – YAB(2)(t – 27) – Gz(t – t3) which is identical to (9.42). I (Robert_W_Brown;_Yu-Chung_N_Cheng: E_Mark_Haacke;(z-lib.org).pdf - Adobe Reader File Edit View Window Help Оpen (192 of 978) Tools Fill & Sign Comment 158 100% Sign In • Export PDF • Create PDF v Edit PDF Adobe Acrobat Pro 158 Chapter 9. One-Dimensional Fourier Imaging Easily edit text and images in PDF documents Start Now (T)y (T/2) • Send Files > Store Files rf t, G read t, ADC T. Fig. 9.6: Sequence diagram for a spin echo 1D imaging experiment with a 7-pulse preceding two gradient lobes of opposite polarity. The subscripts on the rf flip angles again denote the direction of the applied magnetic field B1. 图

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given Substitute and Hence Separate the real and imaginary part... View the full answer