probability of observing a window given there is a window is 0.9. After incorporating the observation of a window, what is the robot's new values for P(L1) and P(L2)? 9. [Coding] Your cell phone is constantly trying to keep track of where you are. At any given point in time, for all nearby locations, your phone stores a probability that you are in that location. Right now your phone believes that you are in one of 16 different locations arranged in a grid with the following probabilities (see the figure on the left): Prior Belief of Location P(Observe two bars of signal | Location) 0.05 0.10 0.05 0.05 0.75 0.95 0.75 0.05 0.05 0.10 0.05 0.05 0.05 0.75 0.95 0.75 0.05 0.05 0.10 0.05 0.01 0.05 0.75 0.95 0.05 0.05 0.10 0.05 0.01 0.01 0.05 0.75 Your phone connects to a known cell tower and records two bars of signal. For each grid location L; you know the probability of observing two bars from this particular tower, given that the cell phone is in location L; (see the figure on the right). That value is based on knowledge of the dynamics of this particular cell tower and stochasticity of signal strength. Example: the highlighted cell on the left figure means that you believed there was a 0.05 probability that the user was in the bottom right grid cell prior to observing the cell tower