Problem $10$:$8$ points$)$ Loks A motionless light vertical hanging spring, stiffness constant k$,$ has a relaxed length, Lo$.$ A mass, M is attached to the end of the spring and comes to equilibrium. With the mass and spring at rest, you very slowly pull down on the mass so that the spring stretches an additional length, si$.$ At that point, you give the mass an upward initial speed, v$.$ Veq $=?$ Un$-$stretched spring hangs freely $||$ Spring at its equilibrium position Mass M hangs in equilibrium from spring Which of the following equations will you need to solve to determine the speed, veg of the mass when it passes through the equilibrium position of the spring? Consider the spring, mass and Earth as the system. Mass M pulled down a distances, relative to equilibrium and given an upward speed v $(159\}-0)=(\{$au $$ bau$)$ la $((!$s$-)$Bu $0)=(*5*4\}0)+($zam $$ ogam$)0=(5*4-0)+($zam $$ "qam$)180=((\text{'}$s$-)$Bu $$ o$)+(35*450)+($zamu$$ "gau$)($v