Problem 1. (1 point) Problem 4. (1 point) Find the area of the region enclosed by the two functions y = 6x2 The boundaries of the shaded region are the y-axis, the line y = 1, and y = x2 +5. and the curve y = vx. Find the area of this region by writing x as a function of y and integrating with respect to y. y= Vx Area = Problem 2. (1 point) Area = The area of the region that lies to the right of the y-axis and to the Note: You can click on the graph to enlarge the image. left of the parabola x = 2y -y- (the shaded region in the figure) is given by the integral So (2y-y ) dy. (Turn your head clockwise and think of the region as lying below the curve x = 2y - y from Problem 5. (1 point) y = 0 to y = 2.) Find the area of the region. Find the area of the region that is enclosed between y = 10x2 - x + x and y = x- +21x. The area is * = 2y-y Problem 6. (1 point) Find the area of the region between the curves y = 12 -x2 and Area =_ y=x -6. Area between curves = Problem 3. (1 point) Problem 7. (1 point) Find the area of the shaded region below. Find the area of the region between the curves 4x + y = 12 and x =y. (-3.3)- Area between curves = Problem 8. (1 point) xly-y Find the area of the region between the curves y = x and y = Vx. Area =. Area between curves =Problem 9. (1 point) Problem 10. (1 point) Sketch the region enclosed by 2y = 5\\/x,y = 3, and 2y + 3x = 8. Sketch the region enclosed by the curves given below. Decide whether to integrate with respect to x or y. Then find the area of Decide whether to integrate with respect to x or y, and then find the region. the area of the region. x =49-y, x=yz -49 The area is Area = Problem 11. (1 point) Find the area of the region that is enclosed between y = 12x2 - x + x and y = x2 + 29x. The area is