Problem $(14)$: A pump is being used to lift water from an underground

tank through a pipe of diameter $(d)$ at discharge $(Q).$ The total head

loss in the system can be calculated as $(h_L=K[\frac{V^2}{2}g]),$ where $(V)$ is

the flow velocity in the pipe. The elevation difference between the

pump and tank surface is $(h).$

Given the values of $Q[Li\frac{t}{s}],d[cm],$ and $K[-],$ calculate the maximum

elevation difference $h[cm]$ beyond which cavitation would take place

at the pump entrance. Assume turbulent flow conditions.Q $=34\mathrm{.}185$ lit$/$s

d $=13\mathrm{.}842$ cm

K $=8\mathrm{.}568$