Problem $17.$ Use integration by substitution to evaluate the integrals.

$($a$){\displaystyle \underset{-2}{\overset{2}{}}}\frac{2}{(x+3{)}^4}dx$

$($e$){\displaystyle \underset{0}{\overset{\sqrt[\phantom{2}]{\frac{}{2}}}{}}}xcos{x}^{2}dx$

$($i$){\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\sqrt[\phantom{2}]{3-2x}dx$

$($b$){\displaystyle \underset{0}{\overset{1}{}}}(x^2+\sqrt[\phantom{2}]{x})dx$

$($f$){\displaystyle \underset{1}{\overset{{}^2}{}}}\frac{sin\sqrt[\phantom{2}]{x}}{\sqrt[\phantom{2}]{x}}dx$

$($j$){\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}se{c}^2(3x+2)dx$

$($c$){\displaystyle \underset{\frac{}{2}}{\overset{0}{}}}\frac{1+cos2x}{2}dx$

$($g$){\displaystyle \underset{2}{\overset{5}{}}}\frac{xdx}{\sqrt[\phantom{2}]{1+x^2}}$

$($k$){\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{1}{x^2}cos(\frac{1}{x}-1)dx$

$($d$){\displaystyle \underset{-\frac{}{3}}{\overset{-\frac{}{4}}{}}}(4se{c}^{2}x+\frac{}{x^2})dx$

$($h$){\displaystyle \underset{-4}{\overset{4}{}}}|x|dx$

$($l$){\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{1}{x^2}\sqrt[\phantom{2}]{2-\frac{1}{x}}dx$