Problem $1(8$ marks total$)$:

Block $B$ moves downward with a constant velocity of $20m\frac{m}{s}.$ At

$t=0,$ block $A$ is moving upward with a constant acceleration, and

its velocity is $30m\frac{m}{s}.$ Knowing that at $t=3s$ slider block $C$ has

moved $57mm$ to the right, determine $(a)$ the velocity of slider

block $C$ at $t=0,($b$)$ the accelerations of A and $C,(c)$ the change in

position of block A after $5s.$Block B moves downward with a constant velocity of $610$mm $/$ s Determine: $($a$)$ the velocity of block A $($b$)$ The velocity of block B C$.($c$)$ the velocity of portion D of the cable with respect to block B$.$